2B^2-1C-10=5

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Solution for 2B^2-1C-10=5 equation:


Simplifying
2B2 + -1C + -10 = 5

Reorder the terms:
-10 + 2B2 + -1C = 5

Solving
-10 + 2B2 + -1C = 5

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 2B2 + 10 + -1C = 5 + 10

Reorder the terms:
-10 + 10 + 2B2 + -1C = 5 + 10

Combine like terms: -10 + 10 = 0
0 + 2B2 + -1C = 5 + 10
2B2 + -1C = 5 + 10

Combine like terms: 5 + 10 = 15
2B2 + -1C = 15

Add 'C' to each side of the equation.
2B2 + -1C + C = 15 + C

Combine like terms: -1C + C = 0
2B2 + 0 = 15 + C
2B2 = 15 + C

Divide each side by '2'.
B2 = 7.5 + 0.5C

Simplifying
B2 = 7.5 + 0.5C

Reorder the terms:
-7.5 + B2 + -0.5C = 7.5 + 0.5C + -7.5 + -0.5C

Reorder the terms:
-7.5 + B2 + -0.5C = 7.5 + -7.5 + 0.5C + -0.5C

Combine like terms: 7.5 + -7.5 = 0.0
-7.5 + B2 + -0.5C = 0.0 + 0.5C + -0.5C
-7.5 + B2 + -0.5C = 0.5C + -0.5C

Combine like terms: 0.5C + -0.5C = 0.0
-7.5 + B2 + -0.5C = 0.0

The solution to this equation could not be determined.

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